MATH SOLVE

4 months ago

Q:
# Given the equation square root of quantity 2x plus 8 end quantity equals 6, solve for x and identify if it is an extraneous solution.

Accepted Solution

A:

Answer:Solution: x = 6Step-by-step explanation:Given equation is:[tex]\sqrt{2x+8}=6[/tex]In order to solve the equation both sides will be squared[tex](\sqrt{2x+8})^{2} = (6)^2 \\2x+8 = 36\\2x = 36-8\\2x = 28\\x = 14[/tex]Verifying the solution[tex]\sqrt{2(14)+8} = 6\\ \sqrt{28+8} = 6\\\sqrt{36} = 6\\6 = 6[/tex]